(x+56)+(x^2+2x)=180

Solution for (x+56)+(x^2+2x)=180 equation:

(x+56)+(x^2+2x)=180

We move all terms to the left:

(x+56)+(x^2+2x)-(180)=0

We get rid of parentheses

x^2+x+2x+56-180=0

We add all the numbers together, and all the variables

x^2+3x-124=0

a = 1; b = 3; c = -124;
Δ = b2-4ac
Δ = 32-4·1·(-124)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{505}}{2*1}=\frac{-3-\sqrt{505}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{505}}{2*1}=\frac{-3+\sqrt{505}}{2}
$